View Code of Problem 90

#include <iostream>
#include <math.h>

using namespace std;

int main() {
    int n, m;
    char ch;
    cin >> n>>ch >> m;
    for (int i = n; i <= m; ++i) {
        for (int j = i; j <= m; ++j) {
            int sum = i * i + j * j;
            int b=sqrt(sum);
            if (b<=m&&b*b==sum){
                cout << i << "^2+" << j << "^2=" << b << "^2" << endl;
            }
//            for (int k = j; k <= m; ++k) {
//                if (k * k == sum) {
//                    cout << i << "^2+" << j << "^2=" << k << "^2" << endl;
//                    break;
//                }
//            }

        }
    }

    return 0;
}