View Code of Problem 42

#include<stdio.h>
#include<math.h>
int main(){
	float a,b,c,x1,x2,sum;

	scanf("%f %f %f",&a,&b,&c);

	sum = b*b-4*a*c;
	if(sum<0){
		printf("no answer");
	}
	else if(sum==0){
		x1= (-b)/(2*a);
		x2=x1;
	}else{
		x1= (-b+sqrt(sum))/(2*a);
		x2= (-b-sqrt(sum))/(2*a);
	}

	printf("%.2f %.2f",x1,x2);
	return 0;
}

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