View Code of Problem 42

#include <stdio.h>
#include <math.h>

int main()
{
	//输入a b c，输出 x1 x2
	
	int a,b,c;
	float x1,x2;
	scanf("%d %d %d",&a,&b,&c);

	x1 = ((-b)+sqrt(b*b*1.0-4*a*c))/(2*a);
	x2 = ((-b)-sqrt(b*b*1.0-4*a*c))/(2*a);

	if(x1<x2)
	{
		float temp = x1;
		x1 = x2;
		x2 = temp;
	}

	printf("%.2f %.2f\n",x1,x2);
	
	return 0;
}