View Code of Problem 48

#include<stdio.h>
int main()
{
	int i,n;
	double sum=2,s,a[10],b[10];
	scanf("%d",&n);
	a[0]=2;b[0]=1;
	if(n==1)
	{
		printf("%.6f",sum);
	}
	else
	{
		for(i=1;i<n;i++)
		{
			a[i]=a[i-1]+b[i-1];
			b[i]=a[i-1];
			s=a[i]/b[i];
			sum+=s;
		}		
		printf("%.6f",sum);
		return 0;			
	}
	
}

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