View Code of Problem 48

#include<stdio.h>
#include <string.h>
int main(){
	int a[10];
	int b[10];
	a[1]=2;
	b[1]=1;
    int n;
    double sum=0.0;
    scanf("%d",&n);
    int i;
    for(i=2;i<=10;i++){
    	a[i]=a[i-1]+b[i-1];
    	b[i]=a[i-1];
	}
	for(i=1;i<=n;i++){
		sum +=(double)a[i]/(double)b[i];
	}
	printf("%.6f",sum);
	printf("\n");
	return 0;
}