View Code of Problem 48

#include <stdio.h>
main(){
	int i,n;
	float t[10],d[10],sum = 0;
	scanf("%d",&n);
	t[0] = 2.0;t[1] = 3.0;
	for(i = 2;i<10;i++)
		t[i] = t[i-1]+t[i-2];
	d[0] = 1.0;d[1] = 2.0;
	for(i =2;i<10;i++)
		d[i] = d[i-1]+d[i-2];
	for(i = 0;i<n;i++){
		sum+=t[i]/d[i];	
	}
	printf("%.6f\n",sum);
	return 0;
}