View Code of Problem 48

#include<stdio.h>
int main(){
  int i,n,a[100],b[100];
  a[1]=2;a[2]=3;b[1]=1;b[2]=2;
  double sum=0;
  scanf("%d",&n);
  for(i=0;i<n;i++){
    if(i>=2){
    a[i]=a[i-1]+a[i-2];
      b[i]=b[i-1]+b[i-2];
    }
       sum=sum+(a[i]/b[i]);
  }
  printf("%.6f",sum);
  return 0;
}