View Code of Problem 48

#include<stdio.h>
int main()
{
	int n,i;
	double s=0,a[1000],b[1000];
	a[0]=1.0;a[1]=2.0;
	b[0]=2.0;b[1]=3.0;
	scanf("%d",&n);
	for(i=0;i<n;i++)
	{
		if(i>=2)
		{
		a[i]=a[i-1]+a[i-2];
		b[i]=b[i-1]+b[i-2];
		}
		s=s+(b[i]/a[i]);
	}
	printf("%.6f",s);
	return 0;
}