View Code of Problem 88

#include<stdio.h>
int main()
{   int i,n=0,sum=0;
int a[6]={1,4,9,16,25,36};
	int b[6];
	for(i=0;i<6;i++){
		scanf("%d",&b[i]);
		b[i]=a[i]*b[i];
		sum+=b[i];
	}
	if(sum<=36)n=1;
    else {if(sum%36==0)n=sum/36;
           else n=sum/36+1;
	}
	printf("最少需要%d个箱子",n);
   return 0;
}