View Code of Problem 71

#include<stdio.h>
#include<math.h>

int main(){
	int i,n;
	int a[100],b[100];
	double sum;	
	scanf("%d",&n);
	a[0]=2;
	a[1]=3;
	b[0]=1;
	b[1]=2;
	for(sum=1.0*a[0]/b[0]+1.0*a[1]/b[1],i=2;i<n;i++)
	{
		a[i]=a[i-1]+a[i-2];
		b[i]=b[i-1]+b[i-2];
		sum+=1.0*a[i]/b[i];
	}
	if(n==1)
		printf("%0.2f",1.0*a[0]/b[0]);
	else if(n==2)
		printf("%0.2f",1.0*a[0]/b[0]+1.0*a[1]/b[1]);
	else
		printf("%0.2f",sum);	
	return 0;
}