View Code of Problem 67

#include<stdio.h>
int main()
{
	int a,b,c,d;
	int e,f,g,h;
	double k1,k2;
	while( scanf("%d %d %d %d\n%d %d %d %d",&a,&b,&c,&d,&e,&f,&g,&h)!=EOF )
	{
		if( a!=c && e!=g )
		{
			k1 = (d-b)/(c-a);
			k2 = (h-f)/(g-e);
			if(k1 == k2)
			{
				printf("No\n");
			}
			else
			{
				printf("Yes\n");
			}
		}
		else if(a==c&&e==g)
		{
			printf("No\n");
		 } 
		 else
		 {
		 	printf("Yes\n");
		 }
	}
	return 0;
 } 

Double click to view unformatted code.


Back to problem 67