View Code of Problem 72

#include<stdio.h>
void main(){
   double M,sum=0;
  int n,i;
   scanf("lf% %d",&M,&n);
   sum=M;
   for(i=1;i<n;i++){
     M=M/2;
     sum+=M;
     if(i>0)
       sum+=M;
     if(i==n-1)
       M=M/2;
     
  }
	printf("%.2lf %.2lf\n",M,sum);
}