View Code of Problem 72

#include<stdio.h>

double result1(double a,double b){
 for(int i=0;i<b;i++)
    a/=2;
 return a;
}

double result2(double a,double b){
    double sum=0;
    for(int j=0;j <b;j++){
        sum+=a*1.5;
        a/=2;
    }
return  sum-a;
}

int main(){
    double m;
    double n;
    scanf("%lf%lf",&m,&n);
    printf("%.2lf %.2lf",result1(m,n),result2(m,n));
    return 0;
}