View Code of Problem 48

#include<stdio.h>

int main()
{
	int n, i;
	int a[15], b[15];
	double result = 0;
	a[1] = 2; a[2] = 3;
	b[1] = 1; b[2] = 2;
	scanf("%d", &n);
	for(i = 3; i <= n; i++ )
	{ 
		a[i] = a[i - 1] + a[i - 2];
		b[i] = b[i - 1] + b[i - 2];
	}
	for(i = 1; i <= n; i++ )
	{
		result +=(double)a[i] / (double)b[i];

	}
	printf("%.6f", result); 
	return 0;
}