View Code of Problem 87

#include <stdio.h>
void main(){
	int all,min,max;
	scanf("%d",&all);
	if(all%2==1) printf("0 0\n");
	else{
	 min=all/4+all%4/2;//all%4/2=脚数能整除4的就为0，能整除2但不能整除4就为1
	 max=all/2;
	 printf("%d %d\n",min,max);
    }
}