View Code of Problem 96

#include<stdio.h>
#include<math.h>

int main()
{
    double n,sum;
    char s[2];
    scanf("%lf",&n);
    gets(s);
    while(n != 0)
    {
        if(s[0] == 'K')
            sum = n*(pow(1024,1)-pow(1000,1));
        if(s[0] == 'M')
            sum = n*(pow(1024,2)-pow(1000,2));
        if(s[0] == 'G')
            sum = n*(pow(1024,3)-pow(1000,3));
        if(s[0] == 'T')
            sum = n*(pow(1024,4)-pow(1000,4));
        printf("%.0lf\n",sum);
        scanf("%lf",&n);
        gets(s);
    }
    return 0;
}

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