View Code of Problem 48

#include<stdio.h>	
int main()
{
	int a[10000];
	int n,i;
	double sum=0;
	scanf("%d",&n);
	a[0]=1;a[1]=2;
	for(i=2;i<=n;i++)
		a[i]=a[i-1]+a[i-2];
	for(i=0;i<n;i++)
		sum+=(double)a[i+1]/a[i];
	printf("%.6lf",sum);
}