View Code of Problem 31
#include <stdio.h>
int main(){
int n;
while(scanf("%d",&n)!=EOF){
int a=(n*5-4)*21+2;
printf("%d\n",a);
}
return 0;
} |
Double click to view unformatted code.
Back to problem 31
#include <stdio.h>
int main(){
int n;
while(scanf("%d",&n)!=EOF){
int a=(n*5-4)*21+2;
printf("%d\n",a);
}
return 0;
} |
Double click to view unformatted code.