View Code of Problem 48

#include <stdio.h>
int main(){
	double a[11]={1,2},ever,sum=0;
	int i,n;
	for(i=2;i<11;i++){
		a[i]=a[i-1]+a[i-2];
	}
	scanf("%d",&n);
	for(i=1;i<=n;i++){
		ever=a[i]/a[i-1];
		sum+=ever;
	}
	printf("%lf",sum);
}

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