View Code of Problem 42

#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;

int main()
{
    double a,b,c;
    cin>>a>>b>>c;
    double ans1 = ( -b+(sqrt(b*b-4*a*c)) ) / (2*a);
    double ans2 = ( -b-(sqrt(b*b-4*a*c)) ) / (2*a);

    printf("%.2f %.2f\n",ans1,ans2);
    return 0;
}