View Code of Problem 48

#include<iostream> 
#include <stdio.h>
#include <math.h>
#include "string.h"
using namespace std;
double function(double n)
{
	if(n==1)
	return 1;
	else if(n==2)
	return 2;
	else
	return function(n-1)+function(n-2);
}
int main(){
	int n;
	cin>>n;
	double sum=0;
	for(int i=1;i<=n;i++){
		sum=sum+(function(i+1)/function(i));
	}
printf("%.6lf",sum);
	return 0;
}