View Code of Problem 118

#include <cstdio>
#include <iostream>
#include <cmath>
using namespace std;

double taix(double n){
	double sum=0;
	if(n<=3){
		sum=5;
	}
	else{
		double remain=n-3;
		sum=5+remain*1.5;
	} 
	return sum;
}

int main(){
	double n; 
	int count=0;
	while(cin>>n){
		count++;
		double sum=taix(n);
		cout<<"Case #"<<count<<": "<<ceil(sum)<<endl;
	}
}