View Code of Problem 48

#include <stdio.h>
#include <stdlib.h>
int main()
{
	int a[11],i,j,n;
    double b[10],sum;
    a[0]=1;a[1]=2;
    for(i=2;i<11;i++)
    a[i]=a[i-1]+a[i-2];
    for(i=0;i<10;i++)
    b[i]=(double)a[i+1]/(double)a[i];
    scanf("%d",&n);
    sum=0;
    for(i=0;i<n;i++)
    sum+=b[i];
    printf("%.6f",sum);
    
	system("pause");
	return 0;
}

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