View Code of Problem 72

#include<stdio.h>
int main() {
	int i;
	double sum, M, N;
	scanf("%lf %lf", &M, &N);
	sum = 0;
	for (i = 1; i <= N; i++) {
		if(i!=N)
			sum = sum + M + M / 2;
		else {
			sum += M;
		}
		M = M / 2;
	}
	printf("%.2lf %.2lf\n",M,sum);
	return 0;
}