View Code of Problem 42

#include<stdio.h>
#include<math.h>
int main ()

{
	int a,b,c,m;
	double n1,n2;
	scanf("%d%d%d",&a,&b,&c);
	n1=(-b+sqrt(b*b-4*a*c))/2*a;
	n2=(-b-sqrt(b*b-4*a*c))/2*a;
	if (n1>n2)
	{
		printf("%d%d",n1,n2);
	}
	else
	{
		printf("%d%d",n2,n1);
	}
		return 0;
}

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