View Code of Problem 42

#include<stdio.h>
#include<math.h>
int main ()

{
	int a,b,c;
	scanf("%d%d%d",&a,&b,&c);
	double n1,n2;
	
	n1=( - b + sqrt( b * b- 4 * a * c ) ) / ( 2 * a );
	n2=(-b- sqrt(b*b-4*a*c)) /(2*a);
	if (n1>=n2)
	{
		printf("%.2f%.2f\n",n1,n2);
	}
	else
	{
		printf("%.2f%.2f\n",n2,n1);
	}
		return 0;
}