View Code of Problem 72

#include<cstdio>
#include<cstring>
#include<cmath>
using namespace std;
int main(){
	int m, n,i;
	double x, y;
	scanf("%d%d", &m, &n);
	x = m / (pow(2.0, n));
	y = m;
	for (i = 1; i < n; i++)
	{
		y = y + m / pow(2.0, i-1);
	}
	printf("%.2lf %.2lf\n", x, y);

	return 0;
}

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