View Code of Problem 9

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int a[5];
int f[5] = {5, 8, 10, 15, 20};

int main()
{
    int t;
    char n[100];
    int kk = 0;
    while(scanf("%d", &t) != EOF)
    {
        kk++;
        for (int i = 0; i < 5; i++) {
            a[i] = 0;
        }
        getchar();
        while (t--) {
            gets(n);
            if (strcmp(n, "Pleasant goat") == 0) {
                a[0]++;
            }
            else if(strcmp(n, "Pretty goat") == 0)
            {
                a[1]++;
            }
            else if(strcmp(n, "Athletic goat") == 0)
            {
                a[2]++;
            }
            else if(strcmp(n, "Lazy goat") == 0)
            {
                a[3]++;
            }
            else if(strcmp(n, "Slow goat") == 0)
            {
                a[4]++;
            }
        }
        int count = 0;
        
        if (a[2] > 0 && (a[0] + a[1] + a[2] + a[3] + a[4] >= 10)) {
            count += 50;
        }
        for (int i = 0; i < 5; i++) {
            count += a[i] * f[i];
        }
        
        printf("Case #%d: %d\n", kk, count);
    }
}