View Code of Problem 48

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <limits.h>
#include <math.h>

double s[10] = {2/1.0, 3/2.0, 5/3.0, 8/5.0, 13/8.0, 21/13.0, 34/21.0, 55/34.0, 89/55.0, 144/89.0};

int main()
{
    int n;
    while (scanf("%d", &n) != EOF) {
        double sum = 0;
        for(int i = 0; i < n; i++)
            sum += s[i];
        printf("%.6lf\n", sum);
    }
}

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