View Code of Problem 26
#include<iostream>
using namespace std;
int main()
{
double F;
double C;
while (cin >> F) {
C = (5 / 9)*(F - 32);
printf("%.2lf\n", C);
}
} |
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Back to problem 26
#include<iostream>
using namespace std;
int main()
{
double F;
double C;
while (cin >> F) {
C = (5 / 9)*(F - 32);
printf("%.2lf\n", C);
}
} |
Double click to view unformatted code.