View Code of Problem 42

#include<stdio.h>
#include<math.h>
main()
{
	int a,b,c;
	double x,y,d;
	scanf("%d%d%d",&a,&b,&c);
	d=b*b-4*a*c;
	if(d>=0)
	{
		x=(-b+sqrt(d))/2*a;
		y=(-b-sqrt(d))/2*a;
	}
	else
	printf("请重新输入！");
	printf("%.2f %.2f",x,y);
	return 0;
	 
}