View Code of Problem 48

#include<stdio.h>
int main()
{
int n,i,j,a[20],b[20];
double c[20];
double sum=0.0;
  scanf("%d",&n);
a[0]=2,a[1]=3;
b[0]=1,b[1]=2;
for(i=2;i<n;i++)
{a[i]=a[i-1]+a[i-2];
b[i]=b[i-1]+b[i-2];
} 
for(i=0;i<n;i++)
{
	c[i]=(double)a[i]/b[i];
sum+=c[i];
}
printf("%.6lf",sum);

}