View Code of Problem 48

#include<stdio.h>

int main(){
	int i,n;
	double sum;
	int a[11]={0},b[11]={0};
	scanf("%d",&n);
	a[0]=2; a[1]=3;
	b[0]=1; b[1]=2;
	sum=0;
	if (n==1) 
		sum=1.0*a[0]/b[0];
	else if (n>=2) 
		sum=1.0*a[0]/b[0]+1.0*a[1]/b[1];
    for(i=2;i<n;i++)
	{
		a[i]=a[i-1]+a[i-2];
		b[i]=b[i-1]+b[i-2];
		sum+=1.0*a[i]/b[i];
	}
	printf("%0.6f",sum);
	return 0;
}