View Code of Problem 8

#include <iostream>
using namespace std;

int main(){
  int n,day[13]={-1,31,28,31,30,31,30,31,31,30,31,30,31},l_num,prior,prev,sum;
    char num[7];
  scanf("%d",&n);
  
  while(n--){
    scanf("%s",&num);
    l_num = num[6]-'0';//字符转数字
    
    if(l_num == 0)
      prev = 9;
    else
      prev = l_num - 1;
    
    if(l_num == 9)
      prior = 0;
    else
      prior = l_num + 1;
    
    sum = 0;
    for(int j = 1;j <= 12;j ++){
      for(int k = 1;k <= day[j];k ++){
        if(k%10 == prev || k%10 == prior)
          continue;
        else
          sum ++;
      }
    }
    printf("%d\n",sum);
  }
  return 0;
}