View Code of Problem 72

#include<stdio.h>

int main(){
	int i,n,j;
	double m,x,a[1000],sum;
	scanf("%lf%d",&m,&n);
	a[0]=m;
	sum=m;
	for (j=i=0;i<n;i++)
	{
		x=a[i]/2;
		a[++j]=x;
		sum+=2*x;
	}
	sum-=2*x;	
	printf("%0.2f %0.2f",x,sum);
	return 0;
}