View Code of Problem 48

#include<stdio.h>
int main()
{
  int n,i;
  double zi=2,mu=1,sum=0,temp,t;
  scanf("%d",&n);
  for(i=0;i<n;i++)
  {
    t=zi/mu;
    sum+=t;
	temp=mu;
    mu=zi;
    zi+=temp; 
  }
  printf("%.6lf",sum);
  return 0;
}