View Code of Problem 70

#include<stdio.h>
int main()
{
	int n,c,x;
	scanf("%d",&n);
	c=n/100000;
	
	switch(c)
	{
	case 0:	x=n*0.1;
			break;
	case 1:	x=10000+(n-100000)*0.075;
			break;
	case 2:	
	case 3:	x=10000+7500+(n-200000)*0.05;
			break;
	case 4:	
	case 5:	x=(100000)*0.1+100000*0.075+(200000)*0.05+(n-400000)*0.03;
			break; 
	case 6:
	case 7:
	case 8:
	case 9:	x=(100000)*0.1+100000*0.075+(200000)*0.05+(400000)*0.03+(n-600000)*0.015;
 			break;
	case 10:x=(100000)*0.1+100000*0.075+(200000)*0.05+(400000)*0.03+(600000)*0.015+(n-100000)*0.01;
			break;
	default:;
	}
	printf("%d",x);
	return 0;
}