View Code of Problem 71

#include<stdio.h>
void main(){
	int n,i,x1=2,x2=3,y1=1,y2=2,x,y;
	double sum=2/1.0+3/2.0;
	scanf("%d",&n);
	if(n==1)
		printf("%.2f",2/1.0);
	else if(n==2)
		printf("%.2f",2/1.0+3/2.0);
	else{
		for(i=2;i<n;i++){
			x=x1+x2;
			y=y1+y2;
			sum=sum+x/(y*1.0);
			x1=x2;
			x2=x;
			y1=y2;
			y2=y;
		}
		printf("%.2f",sum);
	}
}

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