View Code of Problem 70

#include<stdio.h>
int main()
{
  float I,m;
  scanf("%d",&I);
  if(I<=100000)
     m=I*0.1;
  else if(I>100000&&I<200000)
    m=100000*0.1+(I-100000)*0.075;
  else if(I>200000&&I<400000)
    m=100000*0.1+(200000-100000)*0.075+(I-200000)*0.05;
  else if(I>400000&&I<600000)
    m=m+(I-400000)*0.03;
  else if(I>600000&&I<1000000)
    m=m+(I-600000)*0.015;
  else if(I>1000000)
    m=m+(I-1000000)*0.01;
  printf("%.2f",m);
    return 0;
 }
    
    

Double click to view unformatted code.


Back to problem 70