View Code of Problem 118

#include<stdio.h>
#include <string.h>
#include <math.h>
int main(){
	int n;
	int i;
	double cost=0;
	for(i=1;scanf("%d",&n)!=EOF;i++){
		if(n<=3){
			printf("Case #%d: 5\n",i);
		}
		else{
			cost=5+(n-3)*1.5+0.5;
			printf("Case #%d: %d\n",i,(int)cost);
		}
	}
	
	printf("\n");
	return 0;
}