View Code of Problem 6

#include<stdio.h>
int main()
{
	int t,n,a[50001],b[50001],cha,i,j,k;
	scanf("%d",&t);
	for(i=0;i<t;i++)
	{
		scanf("%d",&n);
		for(j=0;j<n;j++)
		{
			scanf("%d%d",&a[j],&b[j]);
		}
		cha=b[0]-a[0];
		for(k=1;k<n;k++)
		{
			if(cha!=b[k]-a[k])
			{
				printf("NO\n");
				break;
			}
		}
		if(k==n)
			printf("YES\n");

	}
	return 0;
}

Double click to view unformatted code.


Back to problem 6