View Code of Problem 42

#include<stdio.h>
#include<math.h>
int main()
{
  int a,b,c;
  double d,x1,x2;
  printf("请输入a,b,c的值");
  scanf("%d,%d,%d",&a,&b,&c);
  d=sqrt(b*b+4*a*c);
  if(d>0)
  {
   x1=(-b+d)/(2*a);
   x2=(-b-d)/(2*a);
   printf("%.2f,%.2f",x1,x2);
  }
  return 0;
}