View Code of Problem 70

#include <stdio.h>
int main()
{
	int n,temp,sum;
	scanf("%d",&n);
	if(n>1000000)
	{
		sum=10000+0.075*100000+200000*0.05+200000*0.03+200000*0.015+(n-1000000)*0.01;
		printf ("%d",sum);
	}
	temp=n-1;
	switch (temp/100000)
	{
	case 0:sum=0.1*n;break;
	case 1:sum=10000+0.075*(n-100000);break;
	case 2:
	case 3:sum=10000+0.075*100000+(n-200000)*0.05;break;
	case 4:
	case 5:sum=10000+0.075*100000+200000*0.05+(n-400000)*0.03;break;
	default:sum=10000+0.075*100000+200000*0.05+200000*0.03+(n-600000)*0.015;break;
	}
	printf("%d",sum);
	return 0;
}