View Code of Problem 115

#include<bits/stdc++.h>
using namespace std;
int main() {
	int n;
	long long a[31];
	a[1]=1;
	for(long long i=2;i<31;i++)
	{
		a[i]=a[i-1]+pow(2,i-1);
	}
	while(scanf("%d",&n)!=EOF)
	{
		printf("%lld %d\n",a[n],n*100000);
	}
}

Double click to view unformatted code.


Back to problem 115