View Code of Problem 56

#include<stdio.h>
#include<math.h>
int main()
{
	int a[3],b[3],sum1,sum2;
	scanf("%d:%d:%d\n",&a[0],&a[1],&a[2]);
	scanf("%d:%d:%d",&b[0],&b[1],&b[2]);
	sum1=a[0]*3600+a[1]*60+a[2];
	sum2=b[0]*3600+b[1]*60+b[2];
	sum1=abs(sum1-sum2);
	printf("%02d:%02d:%02d",sum1/3600,(sum1%3600)/60,(sum1%3600)%60);
	return 0;
}