View Code of Problem 48

#include <stdio.h>
#include <math.h>

int main(int argc, const char * argv[]) {
    int n;
    double fz[10], fm[10];
    double sum = 0;
    
    scanf("%d", &n);
    fz[0] = 2;
    fm[0] = 1;
    
    for(int i = 0; i < n; i++) {
        sum += fz[i] / fm[i];
        fm[i + 1] = fz[i];
        fz[i + 1] = fz[i] + fm[i];
    }
    
    printf("%.6f\n", sum);
    return 0;
}