View Code of Problem 48

#include <stdio.h>
int main()
{
	double sum = 0;
	int n;
	scanf("%d", &n);
	int a[10] = { 2,3 }, b[10] = { 1,2 };
	for (int i = 2; i < 10; i++)
	{
		a[i] = a[i - 2] + a[i - 1];
		b[i] = b[i - 2] + b[i - 1];
	}
	for (int i = 0; i < n; i++)
		sum += a[i] / (b[i]*1.0);
	printf("%.6f", sum);
	return 0;
}