View Code of Problem 71

#include<stdio.h>
int main()
{
	int i,n,fz=1,fm=1;
	double sum=0;
	scanf("%d",&n);
	for(i=1;i<=n;i++)
	{
		fz=fz+fm;
		fm=fz-fm;
		sum=sum+(double)fz/fm;
	}
	printf("%.2f\n",sum);
	return 0;
 }