View Code of Problem 48

#include<stdio.h>
int main()
{
	int n,i,fz=1,fm=1;
	double sum=0;
	scanf("%d",&n);
	for(i=0;i<n;i++)
	{
		fz=fz+fm;
		fm=fz-fm;
		sum=sum+(double)fz/fm;
	}
	printf("%.6f",sum);
	return 0;
 } 

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