View Code of Problem 71

#include<stdio.h>

int main(void)
{
	int n, i=1, j=2, k;
	double sum=0;
	scanf("%d",&n);
	for(k=0;k<n;k++)
	{
		sum=sum+(double)j/i;
		j=j+i;
		i=j-i;
	}
	printf("%.2lf",sum);
	return 0;
}